Base | Representation |
---|---|
bin | 111011101000010… |
… | …100111001101101 |
3 | 2120201110222000012 |
4 | 323220110321231 |
5 | 4022102131432 |
6 | 243134343005 |
7 | 33535330064 |
oct | 7350247155 |
9 | 2521428005 |
10 | 1000427117 |
11 | 473795778 |
12 | 23b05aa65 |
13 | 12c359711 |
14 | 96c1d1db |
15 | 5cc67cb2 |
hex | 3ba14e6d |
1000427117 has 2 divisors, whose sum is σ = 1000427118. Its totient is φ = 1000427116.
The previous prime is 1000427107. The next prime is 1000427147. The reversal of 1000427117 is 7117240001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 987279241 + 13147876 = 31421^2 + 3626^2 .
It is a cyclic number.
It is not a de Polignac number, because 1000427117 - 216 = 1000361581 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1000427092 and 1000427101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1000427107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500213558 + 500213559.
It is an arithmetic number, because the mean of its divisors is an integer number (500213559).
Almost surely, 21000427117 is an apocalyptic number.
It is an amenable number.
1000427117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000427117 is an equidigital number, since it uses as much as digits as its factorization.
1000427117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 392, while the sum is 23.
The square root of 1000427117 is about 31629.5291934610. The cubic root of 1000427117 is about 1000.1423520683.
Adding to 1000427117 its reverse (7117240001), we get a palindrome (8117667118).
The spelling of 1000427117 in words is "one billion, four hundred twenty-seven thousand, one hundred seventeen".
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