10004340013127 has 2 divisors, whose sum is σ = 10004340013128. Its totient is φ = 10004340013126.

The previous prime is 10004340013103. The next prime is 10004340013133. The reversal of 10004340013127 is 72131004340001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10004340013127 - 2¹⁰ = 10004340012103 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10004340013096 and 10004340013105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10004340013147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002170006563 + 5002170006564.

It is an arithmetic number, because the mean of its divisors is an integer number (5002170006564).

Almost surely, 2^{10004340013127} is an apocalyptic number.

10004340013127 is a deficient number, since it is larger than the sum of its proper divisors (1).

10004340013127 is an equidigital number, since it uses as much as digits as its factorization.

10004340013127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 10004340013127 its reverse (72131004340001), we get a palindrome (82135344353128).

The spelling of 10004340013127 in words is "ten trillion, four billion, three hundred forty million, thirteen thousand, one hundred twenty-seven".