Base | Representation |
---|---|
bin | 10010101000100111… |
… | …00001110101100011 |
3 | 221211012221010120121 |
4 | 21110103201311203 |
5 | 130442102340232 |
6 | 4332415421111 |
7 | 502626326131 |
oct | 112423416543 |
9 | 27735833517 |
10 | 10004340067 |
11 | 4274209847 |
12 | 1b32524797 |
13 | c35879a67 |
14 | 6ac972751 |
15 | 3d8468d97 |
hex | 2544e1d63 |
10004340067 has 2 divisors, whose sum is σ = 10004340068. Its totient is φ = 10004340066.
The previous prime is 10004340019. The next prime is 10004340077. The reversal of 10004340067 is 76004340001.
It is a strong prime.
It is an emirp because it is prime and its reverse (76004340001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10004340067 - 219 = 10003815779 is a prime.
It is not a weakly prime, because it can be changed into another prime (10004340077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002170033 + 5002170034.
It is an arithmetic number, because the mean of its divisors is an integer number (5002170034).
Almost surely, 210004340067 is an apocalyptic number.
10004340067 is a deficient number, since it is larger than the sum of its proper divisors (1).
10004340067 is an equidigital number, since it uses as much as digits as its factorization.
10004340067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 10004340067 its reverse (76004340001), we get a palindrome (86008680068).
The spelling of 10004340067 in words is "ten billion, four million, three hundred forty thousand, sixty-seven".
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