Base | Representation |
---|---|
bin | 10010101000100111… |
… | …10000011110011111 |
3 | 221211020001011211111 |
4 | 21110103300132133 |
5 | 130442111300111 |
6 | 4332421002451 |
7 | 502626666013 |
oct | 112423603637 |
9 | 27736034744 |
10 | 10004400031 |
11 | 427424a8aa |
12 | 1b32553427 |
13 | c3589b142 |
14 | 6ac98a543 |
15 | 3d847ba21 |
hex | 2544f079f |
10004400031 has 2 divisors, whose sum is σ = 10004400032. Its totient is φ = 10004400030.
The previous prime is 10004400017. The next prime is 10004400041. The reversal of 10004400031 is 13000440001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10004400031 - 29 = 10004399519 is a prime.
It is a super-2 number, since 2×100044000312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10004399984 and 10004400020.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10004400041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002200015 + 5002200016.
It is an arithmetic number, because the mean of its divisors is an integer number (5002200016).
Almost surely, 210004400031 is an apocalyptic number.
10004400031 is a deficient number, since it is larger than the sum of its proper divisors (1).
10004400031 is an equidigital number, since it uses as much as digits as its factorization.
10004400031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 10004400031 its reverse (13000440001), we get a palindrome (23004840032).
The spelling of 10004400031 in words is "ten billion, four million, four hundred thousand, thirty-one".
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