10005331220433 has 64 divisors (see below), whose sum is σ = 15336921600000. Its totient is φ = 6441542304192.

The previous prime is 10005331220393. The next prime is 10005331220459. The reversal of 10005331220433 is 33402213350001.

10005331220433 is a `hidden beast` number, since 1 + 0 + 0 + 0 + 5 + 3 + 3 + 1 + 220 + 433 = 666.

It is not a de Polignac number, because 10005331220433 - 2¹⁸ = 10005330958289 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 10005331220397 and 10005331220406.

It is not an unprimeable number, because it can be changed into a prime (10005331220473) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 714710568 + ... + 714724566.

It is an arithmetic number, because the mean of its divisors is an integer number (239639400000).

Almost surely, 2^{10005331220433} is an apocalyptic number.

It is an amenable number.

10005331220433 is a deficient number, since it is larger than the sum of its proper divisors (5331590379567).

10005331220433 is a wasteful number, since it uses less digits than its factorization.

10005331220433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19331 (or 19325 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 27.

Adding to 10005331220433 its reverse (33402213350001), we get a palindrome (43407544570434).

The spelling of 10005331220433 in words is "ten trillion, five billion, three hundred thirty-one million, two hundred twenty thousand, four hundred thirty-three".