100091476521941 has 2 divisors, whose sum is σ = 100091476521942. Its totient is φ = 100091476521940.

The previous prime is 100091476521931. The next prime is 100091476521961. The reversal of 100091476521941 is 149125674190001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71470538700625 + 28620937821316 = 8454025^2 + 5349854^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100091476521941 is a prime.

It is a super-3 number, since 3×100091476521941³ (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 100091476521941.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100091476521931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50045738260970 + 50045738260971.

It is an arithmetic number, because the mean of its divisors is an integer number (50045738260971).

Almost surely, 2^{100091476521941} is an apocalyptic number.

It is an amenable number.

100091476521941 is a deficient number, since it is larger than the sum of its proper divisors (1).

100091476521941 is an equidigital number, since it uses as much as digits as its factorization.

100091476521941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 50.

The spelling of 100091476521941 in words is "one hundred trillion, ninety-one billion, four hundred seventy-six million, five hundred twenty-one thousand, nine hundred forty-one".