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10009999013941 is a prime number
BaseRepresentation
bin1001000110101010001001…
…1011110111100000110101
31022102221120001010210100001
42101222202123313200311
52303000434221421231
633142310254351301
72052125051511403
oct221524233674065
938387501123301
1010009999013941
11320a242535203
1211580084bb531
13577c2888bc14
142686b50b6473
151255b2ba8b61
hex91aa26f7835

10009999013941 has 2 divisors, whose sum is σ = 10009999013942. Its totient is φ = 10009999013940.

The previous prime is 10009999013873. The next prime is 10009999013957. The reversal of 10009999013941 is 14931099990001.

10009999013941 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6268563764100 + 3741435249841 = 2503710^2 + 1934279^2 .

It is a cyclic number.

It is not a de Polignac number, because 10009999013941 - 215 = 10009998981173 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10009999013041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5004999506970 + 5004999506971.

It is an arithmetic number, because the mean of its divisors is an integer number (5004999506971).

Almost surely, 210009999013941 is an apocalyptic number.

It is an amenable number.

10009999013941 is a deficient number, since it is larger than the sum of its proper divisors (1).

10009999013941 is an equidigital number, since it uses as much as digits as its factorization.

10009999013941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 708588, while the sum is 55.

The spelling of 10009999013941 in words is "ten trillion, nine billion, nine hundred ninety-nine million, thirteen thousand, nine hundred forty-one".