Base | Representation |
---|---|
bin | 1001000110101010001001… |
… | …1011110111100000110101 |
3 | 1022102221120001010210100001 |
4 | 2101222202123313200311 |
5 | 2303000434221421231 |
6 | 33142310254351301 |
7 | 2052125051511403 |
oct | 221524233674065 |
9 | 38387501123301 |
10 | 10009999013941 |
11 | 320a242535203 |
12 | 11580084bb531 |
13 | 577c2888bc14 |
14 | 2686b50b6473 |
15 | 1255b2ba8b61 |
hex | 91aa26f7835 |
10009999013941 has 2 divisors, whose sum is σ = 10009999013942. Its totient is φ = 10009999013940.
The previous prime is 10009999013873. The next prime is 10009999013957. The reversal of 10009999013941 is 14931099990001.
10009999013941 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6268563764100 + 3741435249841 = 2503710^2 + 1934279^2 .
It is a cyclic number.
It is not a de Polignac number, because 10009999013941 - 215 = 10009998981173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10009999013041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5004999506970 + 5004999506971.
It is an arithmetic number, because the mean of its divisors is an integer number (5004999506971).
Almost surely, 210009999013941 is an apocalyptic number.
It is an amenable number.
10009999013941 is a deficient number, since it is larger than the sum of its proper divisors (1).
10009999013941 is an equidigital number, since it uses as much as digits as its factorization.
10009999013941 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 708588, while the sum is 55.
The spelling of 10009999013941 in words is "ten trillion, nine billion, nine hundred ninety-nine million, thirteen thousand, nine hundred forty-one".
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