1001001020213 has 2 divisors, whose sum is σ = 1001001020214. Its totient is φ = 1001001020212.

The previous prime is 1001001020197. The next prime is 1001001020231. The reversal of 1001001020213 is 3120201001001.

1001001020213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (1001001020231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 998706418609 + 2294601604 = 999353^2 + 47902^2 .

It is a cyclic number.

It is not a de Polignac number, because 1001001020213 - 2⁴ = 1001001020197 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1001001020194 and 1001001020203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001001020263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500500510106 + 500500510107.

It is an arithmetic number, because the mean of its divisors is an integer number (500500510107).

Almost surely, 2^{1001001020213} is an apocalyptic number.

It is an amenable number.

1001001020213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001001020213 is an equidigital number, since it uses as much as digits as its factorization.

1001001020213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 1001001020213 its reverse (3120201001001), we get a palindrome (4121202021214).

The spelling of 1001001020213 in words is "one trillion, one billion, one million, twenty thousand, two hundred thirteen".