Base | Representation |
---|---|
bin | 11101001000100000101… |
… | …11101000110101001111 |
3 | 10112200202112212220111222 |
4 | 32210100113220311033 |
5 | 112400023003340413 |
6 | 2043504243033555 |
7 | 132214522466531 |
oct | 16442027506517 |
9 | 3480675786458 |
10 | 1001002011983 |
11 | 3565825a3376 |
12 | 14200166b8bb |
13 | 73517a5b73c |
14 | 3663d559851 |
15 | 1b0896e3b08 |
hex | e9105e8d4f |
1001002011983 has 2 divisors, whose sum is σ = 1001002011984. Its totient is φ = 1001002011982.
The previous prime is 1001002011959. The next prime is 1001002012013. The reversal of 1001002011983 is 3891102001001.
1001002011983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1001002011983 - 214 = 1001001995599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1001002211983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500501005991 + 500501005992.
It is an arithmetic number, because the mean of its divisors is an integer number (500501005992).
Almost surely, 21001002011983 is an apocalyptic number.
1001002011983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001002011983 is an equidigital number, since it uses as much as digits as its factorization.
1001002011983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 26.
Adding to 1001002011983 its reverse (3891102001001), we get a palindrome (4892104012984).
The spelling of 1001002011983 in words is "one trillion, one billion, two million, eleven thousand, nine hundred eighty-three".
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