Base | Representation |
---|---|
bin | 101110100111001110… |
… | …0011011001101011111 |
3 | 100120101011102020100122 |
4 | 1131032130123031133 |
5 | 3120001140302033 |
6 | 113552505145155 |
7 | 10142402461613 |
oct | 1351634331537 |
9 | 316334366318 |
10 | 100100322143 |
11 | 394a8027668 |
12 | 1749748b1bb |
13 | 9593536a63 |
14 | 4bb84d7343 |
15 | 290ce54a98 |
hex | 174e71b35f |
100100322143 has 2 divisors, whose sum is σ = 100100322144. Its totient is φ = 100100322142.
The previous prime is 100100322083. The next prime is 100100322149. The reversal of 100100322143 is 341223001001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100100322143 - 230 = 99026580319 is a prime.
It is a super-4 number, since 4×1001003221434 (a number of 45 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100100322149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050161071 + 50050161072.
It is an arithmetic number, because the mean of its divisors is an integer number (50050161072).
Almost surely, 2100100322143 is an apocalyptic number.
100100322143 is a deficient number, since it is larger than the sum of its proper divisors (1).
100100322143 is an equidigital number, since it uses as much as digits as its factorization.
100100322143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 100100322143 its reverse (341223001001), we get a palindrome (441323323144).
The spelling of 100100322143 in words is "one hundred billion, one hundred million, three hundred twenty-two thousand, one hundred forty-three".
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