10010101012211 has 2 divisors, whose sum is σ = 10010101012212. Its totient is φ = 10010101012210.

The previous prime is 10010101012181. The next prime is 10010101012213. The reversal of 10010101012211 is 11221010101001.

10010101012211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10010101012211 is a prime.

It is a super-3 number, since 3×10010101012211³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 10010101012213, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10010101012192 and 10010101012201.

It is not a weakly prime, because it can be changed into another prime (10010101012213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005050506105 + 5005050506106.

It is an arithmetic number, because the mean of its divisors is an integer number (5005050506106).

Almost surely, 2^{10010101012211} is an apocalyptic number.

10010101012211 is a deficient number, since it is larger than the sum of its proper divisors (1).

10010101012211 is an equidigital number, since it uses as much as digits as its factorization.

10010101012211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 10010101012211 its reverse (11221010101001), we get a palindrome (21231111113212).

The spelling of 10010101012211 in words is "ten trillion, ten billion, one hundred one million, twelve thousand, two hundred eleven".