100101106806731 has 2 divisors, whose sum is σ = 100101106806732. Its totient is φ = 100101106806730.

The previous prime is 100101106806677. The next prime is 100101106806733. The reversal of 100101106806731 is 137608601101001.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100101106806731 is a prime.

It is a super-2 number, since 2×100101106806731² (a number of 29 digits) contains 22 as substring.

Together with 100101106806733, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 100101106806691 and 100101106806700.

It is not a weakly prime, because it can be changed into another prime (100101106806733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050553403365 + 50050553403366.

It is an arithmetic number, because the mean of its divisors is an integer number (50050553403366).

Almost surely, 2^{100101106806731} is an apocalyptic number.

100101106806731 is a deficient number, since it is larger than the sum of its proper divisors (1).

100101106806731 is an equidigital number, since it uses as much as digits as its factorization.

100101106806731 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 35.

Adding to 100101106806731 its reverse (137608601101001), we get a palindrome (237709707907732).

The spelling of 100101106806731 in words is "one hundred trillion, one hundred one billion, one hundred six million, eight hundred six thousand, seven hundred thirty-one".