Base | Representation |
---|---|
bin | 10110110000101010011011… |
… | …001010011010111101011011 |
3 | 111010102120110112111120021202 |
4 | 112300222123022122331123 |
5 | 101110024033404012143 |
6 | 552521452054224415 |
7 | 30041031563362424 |
oct | 2660523312327533 |
9 | 433376415446252 |
10 | 100101111000923 |
11 | 2999370859075a |
12 | b28832365510b |
13 | 43b1656b88686 |
14 | 1aa0cc363664b |
15 | b88cd6314ab8 |
hex | 5b0a9b29af5b |
100101111000923 has 2 divisors, whose sum is σ = 100101111000924. Its totient is φ = 100101111000922.
The previous prime is 100101111000911. The next prime is 100101111000977. The reversal of 100101111000923 is 329000111101001.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100101111000923 - 212 = 100101110996827 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100101111000895 and 100101111000904.
It is not a weakly prime, because it can be changed into another prime (100101111050923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050555500461 + 50050555500462.
It is an arithmetic number, because the mean of its divisors is an integer number (50050555500462).
Almost surely, 2100101111000923 is an apocalyptic number.
100101111000923 is a deficient number, since it is larger than the sum of its proper divisors (1).
100101111000923 is an equidigital number, since it uses as much as digits as its factorization.
100101111000923 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 20.
Adding to 100101111000923 its reverse (329000111101001), we get a palindrome (429101222101924).
The spelling of 100101111000923 in words is "one hundred trillion, one hundred one billion, one hundred eleven million, nine hundred twenty-three", and thus it is an aban number.
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