Base | Representation |
---|---|
bin | 10010101001010011… |
… | …00011010001110110 |
3 | 221211121210102202012 |
4 | 21110221203101312 |
5 | 131000042110032 |
6 | 4333143244222 |
7 | 503026362221 |
oct | 112451432166 |
9 | 27747712665 |
10 | 10010113142 |
11 | 42774a2187 |
12 | 1b34449672 |
13 | c36b1b693 |
14 | 6ad6365b8 |
15 | 3d8c096b2 |
hex | 254a63476 |
10010113142 has 4 divisors (see below), whose sum is σ = 15015169716. Its totient is φ = 5005056570.
The previous prime is 10010113117. The next prime is 10010113151. The reversal of 10010113142 is 24131101001.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×100101131422 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2502528284 + ... + 2502528287.
It is an arithmetic number, because the mean of its divisors is an integer number (3753792429).
Almost surely, 210010113142 is an apocalyptic number.
10010113142 is a deficient number, since it is larger than the sum of its proper divisors (5005056574).
10010113142 is an equidigital number, since it uses as much as digits as its factorization.
10010113142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5005056573.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 10010113142 its reverse (24131101001), we get a palindrome (34141214143).
The spelling of 10010113142 in words is "ten billion, ten million, one hundred thirteen thousand, one hundred forty-two".
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