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100101221219893 is a prime number
BaseRepresentation
bin10110110000101010100001…
…101110110111111000110101
3111010102120202012220021021211
4112300222201232313320311
5101110024300113014033
6552521511032441421
730041034402255505
oct2660524156677065
9433376665807254
10100101221219893
1129993764821913
12b288354549271
1343b16739695ba
141aa0cd4127a05
15b88ce0d372cd
hex5b0aa1bb7e35

100101221219893 has 2 divisors, whose sum is σ = 100101221219894. Its totient is φ = 100101221219892.

The previous prime is 100101221219887. The next prime is 100101221220019. The reversal of 100101221219893 is 398912122101001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69513872900004 + 30587348319889 = 8337498^2 + 5530583^2 .

It is a cyclic number.

It is not a de Polignac number, because 100101221219893 - 25 = 100101221219861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100101221214893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050610609946 + 50050610609947.

It is an arithmetic number, because the mean of its divisors is an integer number (50050610609947).

Almost surely, 2100101221219893 is an apocalyptic number.

It is an amenable number.

100101221219893 is a deficient number, since it is larger than the sum of its proper divisors (1).

100101221219893 is an equidigital number, since it uses as much as digits as its factorization.

100101221219893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 40.

The spelling of 100101221219893 in words is "one hundred trillion, one hundred one billion, two hundred twenty-one million, two hundred nineteen thousand, eight hundred ninety-three".