Base | Representation |
---|---|
bin | 10110110000101011010000… |
… | …001010000111000111101111 |
3 | 111010102122202111112002112202 |
4 | 112300223100022013013233 |
5 | 101110032344012041421 |
6 | 552522120215052115 |
7 | 30041062610610344 |
oct | 2660532012070757 |
9 | 433378674462482 |
10 | 100102000112111 |
11 | 29994024456098 |
12 | b28853137103b |
13 | 43b176913ba7a |
14 | 1aa0d6975a7cb |
15 | b88d393e010b |
hex | 5b0ad02871ef |
100102000112111 has 2 divisors, whose sum is σ = 100102000112112. Its totient is φ = 100102000112110.
The previous prime is 100102000112099. The next prime is 100102000112119. The reversal of 100102000112111 is 111211000201001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100102000112111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100102000112092 and 100102000112101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100102000112119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50051000056055 + 50051000056056.
It is an arithmetic number, because the mean of its divisors is an integer number (50051000056056).
Almost surely, 2100102000112111 is an apocalyptic number.
100102000112111 is a deficient number, since it is larger than the sum of its proper divisors (1).
100102000112111 is an equidigital number, since it uses as much as digits as its factorization.
100102000112111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 100102000112111 its reverse (111211000201001), we get a palindrome (211313000313112).
The spelling of 100102000112111 in words is "one hundred trillion, one hundred two billion, one hundred twelve thousand, one hundred eleven".
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