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10010303117 is a prime number
BaseRepresentation
bin10010101001010100…
…10001101010001101
3221211122011002100022
421110222101222031
5131000114144432
64333151311525
7503031113123
oct112452215215
927748132308
1010010303117
114277611991
121b3451b5a5
13c36b86ca9
146ad685913
153d8c45b12
hex254a91a8d

10010303117 has 2 divisors, whose sum is σ = 10010303118. Its totient is φ = 10010303116.

The previous prime is 10010303077. The next prime is 10010303123. The reversal of 10010303117 is 71130301001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9727087876 + 283215241 = 98626^2 + 16829^2 .

It is a cyclic number.

It is not a de Polignac number, because 10010303117 - 216 = 10010237581 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10010303095 and 10010303104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10010303717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005151558 + 5005151559.

It is an arithmetic number, because the mean of its divisors is an integer number (5005151559).

Almost surely, 210010303117 is an apocalyptic number.

It is an amenable number.

10010303117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10010303117 is an equidigital number, since it uses as much as digits as its factorization.

10010303117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63, while the sum is 17.

Adding to 10010303117 its reverse (71130301001), we get a palindrome (81140604118).

The spelling of 10010303117 in words is "ten billion, ten million, three hundred three thousand, one hundred seventeen".