Base | Representation |
---|---|
bin | 1001000110101011010100… |
… | …0010011111101110111111 |
3 | 1022102222100210102221010211 |
4 | 2101222311002133232333 |
5 | 2303002104122130142 |
6 | 33142401244213251 |
7 | 2052135561453034 |
oct | 221526502375677 |
9 | 38388323387124 |
10 | 10010311130047 |
11 | 320a3927346a8 |
12 | 1158094b3a227 |
13 | 577c7843c7c7 |
14 | 26870472138b |
15 | 1255d02ac917 |
hex | 91ab509fbbf |
10010311130047 has 2 divisors, whose sum is σ = 10010311130048. Its totient is φ = 10010311130046.
The previous prime is 10010311129999. The next prime is 10010311130201. The reversal of 10010311130047 is 74003111301001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10010311130047 - 219 = 10010310605759 is a prime.
It is a super-2 number, since 2×100103111300472 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10010311100047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005155565023 + 5005155565024.
It is an arithmetic number, because the mean of its divisors is an integer number (5005155565024).
Almost surely, 210010311130047 is an apocalyptic number.
10010311130047 is a deficient number, since it is larger than the sum of its proper divisors (1).
10010311130047 is an equidigital number, since it uses as much as digits as its factorization.
10010311130047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 10010311130047 its reverse (74003111301001), we get a palindrome (84013422431048).
The spelling of 10010311130047 in words is "ten trillion, ten billion, three hundred eleven million, one hundred thirty thousand, forty-seven".
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