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100105500549953 is a prime number
BaseRepresentation
bin10110110000101110100000…
…110011001110001101000001
3111010102222210110012202112202
4112300232200303032031001
5101110112031120044303
6552523455421402545
730041245424052443
oct2660564063161501
9433388713182482
10100105500549953
1129995560351928
12b289149709455
1343b1ba63cc772
141aa11bc5d0493
15b88e91886c88
hex5b0ba0cce341

100105500549953 has 2 divisors, whose sum is σ = 100105500549954. Its totient is φ = 100105500549952.

The previous prime is 100105500549941. The next prime is 100105500549979. The reversal of 100105500549953 is 359945005501001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 58989281480704 + 41116219069249 = 7680448^2 + 6412193^2 .

It is a cyclic number.

It is not a de Polignac number, because 100105500549953 - 24 = 100105500549937 is a prime.

It is a super-2 number, since 2×1001055005499532 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100105500549898 and 100105500549907.

It is not a weakly prime, because it can be changed into another prime (100105500549913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50052750274976 + 50052750274977.

It is an arithmetic number, because the mean of its divisors is an integer number (50052750274977).

Almost surely, 2100105500549953 is an apocalyptic number.

It is an amenable number.

100105500549953 is a deficient number, since it is larger than the sum of its proper divisors (1).

100105500549953 is an equidigital number, since it uses as much as digits as its factorization.

100105500549953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 607500, while the sum is 47.

The spelling of 100105500549953 in words is "one hundred trillion, one hundred five billion, five hundred million, five hundred forty-nine thousand, nine hundred fifty-three".