100110020344121 has 2 divisors, whose sum is σ = 100110020344122. Its totient is φ = 100110020344120.

The previous prime is 100110020344067. The next prime is 100110020344123. The reversal of 100110020344121 is 121443020011001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89029037670400 + 11080982673721 = 9435520^2 + 3328811^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100110020344121 is a prime.

Together with 100110020344123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 100110020344093 and 100110020344102.

It is not a weakly prime, because it can be changed into another prime (100110020344123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055010172060 + 50055010172061.

It is an arithmetic number, because the mean of its divisors is an integer number (50055010172061).

Almost surely, 2^{100110020344121} is an apocalyptic number.

It is an amenable number.

100110020344121 is a deficient number, since it is larger than the sum of its proper divisors (1).

100110020344121 is an equidigital number, since it uses as much as digits as its factorization.

100110020344121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 100110020344121 its reverse (121443020011001), we get a palindrome (221553040355122).

The spelling of 100110020344121 in words is "one hundred trillion, one hundred ten billion, twenty million, three hundred forty-four thousand, one hundred twenty-one".