10011013012111 has 2 divisors, whose sum is σ = 10011013012112. Its totient is φ = 10011013012110.

The previous prime is 10011013012087. The next prime is 10011013012159. The reversal of 10011013012111 is 11121031011001.

It is a weak prime.

It is an emirp because it is prime and its reverse (11121031011001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10011013012111 - 2⁷ = 10011013011983 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10011013012091 and 10011013012100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10011013012711) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005506506055 + 5005506506056.

It is an arithmetic number, because the mean of its divisors is an integer number (5005506506056).

Almost surely, 2^{10011013012111} is an apocalyptic number.

10011013012111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011013012111 is an equidigital number, since it uses as much as digits as its factorization.

10011013012111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 10011013012111 its reverse (11121031011001), we get a palindrome (21132044023112).

The spelling of 10011013012111 in words is "ten trillion, eleven billion, thirteen million, twelve thousand, one hundred eleven".