100111001000053 has 2 divisors, whose sum is σ = 100111001000054. Its totient is φ = 100111001000052.

The previous prime is 100111000999949. The next prime is 100111001000057. The reversal of 100111001000053 is 350000100111001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74741263961809 + 25369737038244 = 8645303^2 + 5036838^2 .

It is a cyclic number.

It is not a de Polignac number, because 100111001000053 - 2³⁷ = 99973562046581 is a prime.

It is a super-2 number, since 2×100111001000053² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100111000999997 and 100111001000042.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100111001000057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055500500026 + 50055500500027.

It is an arithmetic number, because the mean of its divisors is an integer number (50055500500027).

Almost surely, 2^{100111001000053} is an apocalyptic number.

It is an amenable number.

100111001000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

100111001000053 is an equidigital number, since it uses as much as digits as its factorization.

100111001000053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15, while the sum is 13.

Adding to 100111001000053 its reverse (350000100111001), we get a palindrome (450111101111054).

The spelling of 100111001000053 in words is "one hundred trillion, one hundred eleven billion, one million, fifty-three", and thus it is an aban number.