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1001110549981 is a prime number
BaseRepresentation
bin11101001000101101101…
…01101011010111011101
310112201001010010012122211
432210112311223113131
5112400233300044411
62043523121240421
7132220311162043
oct16442665532735
93481033105584
101001110549981
113566288965a3
12142031a93111
13735343a14c9
143664db30393
151b093ed3221
hexe916d6b5dd

1001110549981 has 2 divisors, whose sum is σ = 1001110549982. Its totient is φ = 1001110549980.

The previous prime is 1001110549951. The next prime is 1001110550101. The reversal of 1001110549981 is 1899450111001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 741656828025 + 259453721956 = 861195^2 + 509366^2 .

It is a cyclic number.

It is not a de Polignac number, because 1001110549981 - 223 = 1001102161373 is a prime.

It is a super-2 number, since 2×10011105499812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001110549951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500555274990 + 500555274991.

It is an arithmetic number, because the mean of its divisors is an integer number (500555274991).

Almost surely, 21001110549981 is an apocalyptic number.

It is an amenable number.

1001110549981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001110549981 is an equidigital number, since it uses as much as digits as its factorization.

1001110549981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 40.

The spelling of 1001110549981 in words is "one trillion, one billion, one hundred ten million, five hundred forty-nine thousand, nine hundred eighty-one".