Base | Representation |
---|---|
bin | 11101001000101101101… |
… | …11011000011110100111 |
3 | 10112201001010221220201111 |
4 | 32210112313120132213 |
5 | 112400233403400103 |
6 | 2043523135005451 |
7 | 132220315033033 |
oct | 16442667303647 |
9 | 3481033856644 |
10 | 1001110996903 |
11 | 356629071356 |
12 | 142032069887 |
13 | 735344c9a64 |
14 | 3664dc091c3 |
15 | 1b09407086d |
hex | e916dd87a7 |
1001110996903 has 2 divisors, whose sum is σ = 1001110996904. Its totient is φ = 1001110996902.
The previous prime is 1001110996871. The next prime is 1001110996933. The reversal of 1001110996903 is 3096990111001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1001110996903 - 25 = 1001110996871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1001110996933) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500555498451 + 500555498452.
It is an arithmetic number, because the mean of its divisors is an integer number (500555498452).
Almost surely, 21001110996903 is an apocalyptic number.
1001110996903 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001110996903 is an equidigital number, since it uses as much as digits as its factorization.
1001110996903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13122, while the sum is 40.
The spelling of 1001110996903 in words is "one trillion, one billion, one hundred ten million, nine hundred ninety-six thousand, nine hundred three".
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