100111101101117 has 2 divisors, whose sum is σ = 100111101101118. Its totient is φ = 100111101101116.

The previous prime is 100111101101111. The next prime is 100111101101171. The reversal of 100111101101117 is 711101101111001.

Together with next prime (100111101101171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 67097412072601 + 33013689028516 = 8191301^2 + 5745754^2 .

It is a cyclic number.

It is not a de Polignac number, because 100111101101117 - 2¹⁶ = 100111101035581 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100111101101095 and 100111101101104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100111101101111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055550550558 + 50055550550559.

It is an arithmetic number, because the mean of its divisors is an integer number (50055550550559).

Almost surely, 2^{100111101101117} is an apocalyptic number.

It is an amenable number.

100111101101117 is a deficient number, since it is larger than the sum of its proper divisors (1).

100111101101117 is an equidigital number, since it uses as much as digits as its factorization.

100111101101117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7, while the sum is 17.

Adding to 100111101101117 its reverse (711101101111001), we get a palindrome (811212202212118).

The spelling of 100111101101117 in words is "one hundred trillion, one hundred eleven billion, one hundred one million, one hundred one thousand, one hundred seventeen".