100111110110953 has 2 divisors, whose sum is σ = 100111110110954. Its totient is φ = 100111110110952.

The previous prime is 100111110110939. The next prime is 100111110110983. The reversal of 100111110110953 is 359011011111001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99221461234009 + 889648876944 = 9960997^2 + 943212^2 .

It is an emirp because it is prime and its reverse (359011011111001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100111110110953 is a prime.

It is a super-3 number, since 3×100111110110953³ (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (100111110110983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055555055476 + 50055555055477.

It is an arithmetic number, because the mean of its divisors is an integer number (50055555055477).

Almost surely, 2^{100111110110953} is an apocalyptic number.

It is an amenable number.

100111110110953 is a deficient number, since it is larger than the sum of its proper divisors (1).

100111110110953 is an equidigital number, since it uses as much as digits as its factorization.

100111110110953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 25.

Adding to 100111110110953 its reverse (359011011111001), we get a palindrome (459122121221954).

The spelling of 100111110110953 in words is "one hundred trillion, one hundred eleven billion, one hundred ten million, one hundred ten thousand, nine hundred fifty-three".