100111111000139 has 2 divisors, whose sum is σ = 100111111000140. Its totient is φ = 100111111000138.

The previous prime is 100111111000133. The next prime is 100111111000141. The reversal of 100111111000139 is 931000111111001.

It is a strong prime.

It is an emirp because it is prime and its reverse (931000111111001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100111111000139 - 2⁸ = 100111110999883 is a prime.

Together with 100111111000141, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 100111111000139.

It is not a weakly prime, because it can be changed into another prime (100111111000133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055555500069 + 50055555500070.

It is an arithmetic number, because the mean of its divisors is an integer number (50055555500070).

Almost surely, 2^{100111111000139} is an apocalyptic number.

100111111000139 is a deficient number, since it is larger than the sum of its proper divisors (1).

100111111000139 is an equidigital number, since it uses as much as digits as its factorization.

100111111000139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 20.

The spelling of 100111111000139 in words is "one hundred trillion, one hundred eleven billion, one hundred eleven million, one hundred thirty-nine", and thus it is an aban number.