Search a number
-
+
10011121122151 is a prime number
BaseRepresentation
bin1001000110101110010101…
…0100010111101101100111
31022110001110020120210102101
42101223211110113231213
52303010234001402101
633143013501152531
72052164625334042
oct221534524275547
938401406523371
1010011121122151
11320a76897a766
12115828025b747
135780771b0786
1426878012bc59
1512562b45a401
hex91ae5517b67

10011121122151 has 2 divisors, whose sum is σ = 10011121122152. Its totient is φ = 10011121122150.

The previous prime is 10011121122097. The next prime is 10011121122253. The reversal of 10011121122151 is 15122112111001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10011121122151 - 235 = 9976761383783 is a prime.

It is a super-2 number, since 2×100111211221512 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10011121122551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005560561075 + 5005560561076.

It is an arithmetic number, because the mean of its divisors is an integer number (5005560561076).

Almost surely, 210011121122151 is an apocalyptic number.

10011121122151 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011121122151 is an equidigital number, since it uses as much as digits as its factorization.

10011121122151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40, while the sum is 19.

Adding to 10011121122151 its reverse (15122112111001), we get a palindrome (25133233233152).

The spelling of 10011121122151 in words is "ten trillion, eleven billion, one hundred twenty-one million, one hundred twenty-two thousand, one hundred fifty-one".