10011121201993 has 2 divisors, whose sum is σ = 10011121201994. Its totient is φ = 10011121201992.

The previous prime is 10011121201987. The next prime is 10011121202039. The reversal of 10011121201993 is 39910212111001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9540981967104 + 470139234889 = 3088848^2 + 685667^2 .

It is an emirp because it is prime and its reverse (39910212111001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10011121201993 is a prime.

It is not a weakly prime, because it can be changed into another prime (10011121201903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005560600996 + 5005560600997.

It is an arithmetic number, because the mean of its divisors is an integer number (5005560600997).

Almost surely, 2^{10011121201993} is an apocalyptic number.

It is an amenable number.

10011121201993 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011121201993 is an equidigital number, since it uses as much as digits as its factorization.

10011121201993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 31.

Adding to 10011121201993 its reverse (39910212111001), we get a palindrome (49921333312994).

The spelling of 10011121201993 in words is "ten trillion, eleven billion, one hundred twenty-one million, two hundred one thousand, nine hundred ninety-three".