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100111213113013 is a prime number
BaseRepresentation
bin10110110000110011110101…
…010010111010111010110101
3111010110112112120102000212101
4112300303311102322322311
5101110210231024104023
6552530242325422101
730041540121044314
oct2660636522727265
9433415476360771
10100111213113013
1129997a219aa023
12b28a28286a931
1343b25a6a78aab
141aa15a117a27b
15b891c81431ad
hex5b0cf54baeb5

100111213113013 has 2 divisors, whose sum is σ = 100111213113014. Its totient is φ = 100111213113012.

The previous prime is 100111213112969. The next prime is 100111213113061. The reversal of 100111213113013 is 310311312111001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51150503233764 + 48960709879249 = 7151958^2 + 6997193^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100111213113013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100111213143013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055606556506 + 50055606556507.

It is an arithmetic number, because the mean of its divisors is an integer number (50055606556507).

Almost surely, 2100111213113013 is an apocalyptic number.

It is an amenable number.

100111213113013 is a deficient number, since it is larger than the sum of its proper divisors (1).

100111213113013 is an equidigital number, since it uses as much as digits as its factorization.

100111213113013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 100111213113013 its reverse (310311312111001), we get a palindrome (410422525224014).

The spelling of 100111213113013 in words is "one hundred trillion, one hundred eleven billion, two hundred thirteen million, one hundred thirteen thousand, thirteen".