Base | Representation |
---|---|
bin | 10110110000110011111011… |
… | …001001100101101110101111 |
3 | 111010110112210102012222112211 |
4 | 112300303323021211232233 |
5 | 101110210431200031343 |
6 | 552530300154511251 |
7 | 30041542422633004 |
oct | 2660637311455657 |
9 | 433415712188484 |
10 | 100111311330223 |
11 | 29997a72393076 |
12 | b28a2ab735527 |
13 | 43b25c1216c9b |
14 | 1aa15b02258ab |
15 | b891d1a9479d |
hex | 5b0cfb265baf |
100111311330223 has 2 divisors, whose sum is σ = 100111311330224. Its totient is φ = 100111311330222.
The previous prime is 100111311330157. The next prime is 100111311330269. The reversal of 100111311330223 is 322033113111001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100111311330223 - 245 = 64926939241391 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100111311330194 and 100111311330203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100111311330323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055655665111 + 50055655665112.
It is an arithmetic number, because the mean of its divisors is an integer number (50055655665112).
Almost surely, 2100111311330223 is an apocalyptic number.
100111311330223 is a deficient number, since it is larger than the sum of its proper divisors (1).
100111311330223 is an equidigital number, since it uses as much as digits as its factorization.
100111311330223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 100111311330223 its reverse (322033113111001), we get a palindrome (422144424441224).
The spelling of 100111311330223 in words is "one hundred trillion, one hundred eleven billion, three hundred eleven million, three hundred thirty thousand, two hundred twenty-three".
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