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100111520117053 is a prime number
BaseRepresentation
bin10110110000110100000111…
…100110000011000100111101
3111010110120022222002110020101
4112300310013212003010331
5101110211343122221203
6552530333013521101
730041550536404654
oct2660640746030475
9433416288073211
10100111520117053
112999806a227775
12b28a349643191
1343b26255598a3
141aa15cdc5419b
15b891e508741d
hex5b0d0798313d

100111520117053 has 2 divisors, whose sum is σ = 100111520117054. Its totient is φ = 100111520117052.

The previous prime is 100111520116961. The next prime is 100111520117057. The reversal of 100111520117053 is 350711025111001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94609432120644 + 5502087996409 = 9726738^2 + 2345653^2 .

It is an emirp because it is prime and its reverse (350711025111001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100111520117053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100111520117057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055760058526 + 50055760058527.

It is an arithmetic number, because the mean of its divisors is an integer number (50055760058527).

Almost surely, 2100111520117053 is an apocalyptic number.

It is an amenable number.

100111520117053 is a deficient number, since it is larger than the sum of its proper divisors (1).

100111520117053 is an equidigital number, since it uses as much as digits as its factorization.

100111520117053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1050, while the sum is 28.

Adding to 100111520117053 its reverse (350711025111001), we get a palindrome (450822545228054).

The spelling of 100111520117053 in words is "one hundred trillion, one hundred eleven billion, five hundred twenty million, one hundred seventeen thousand, fifty-three".