100112013017 has 2 divisors, whose sum is σ = 100112013018. Its totient is φ = 100112013016.

The previous prime is 100112013013. The next prime is 100112013091. The reversal of 100112013017 is 710310211001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 59736736921 + 40375276096 = 244411^2 + 200936^2 .

It is an emirp because it is prime and its reverse (710310211001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100112013017 - 2² = 100112013013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100112012986 and 100112013004.

It is not a weakly prime, because it can be changed into another prime (100112013013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056006508 + 50056006509.

It is an arithmetic number, because the mean of its divisors is an integer number (50056006509).

Almost surely, 2^100112013017 is an apocalyptic number.

It is an amenable number.

100112013017 is a deficient number, since it is larger than the sum of its proper divisors (1).

100112013017 is an equidigital number, since it uses as much as digits as its factorization.

100112013017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42, while the sum is 17.

Adding to 100112013017 its reverse (710310211001), we get a palindrome (810422224018).

The spelling of 100112013017 in words is "one hundred billion, one hundred twelve million, thirteen thousand, seventeen".