100112013013 has 2 divisors, whose sum is σ = 100112013014. Its totient is φ = 100112013012.

The previous prime is 100112012989. The next prime is 100112013017. The reversal of 100112013013 is 310310211001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75430974609 + 24681038404 = 274647^2 + 157102^2 .

It is a cyclic number.

It is not a de Polignac number, because 100112013013 - 2⁵ = 100112012981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100112012984 and 100112013002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100112013017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056006506 + 50056006507.

It is an arithmetic number, because the mean of its divisors is an integer number (50056006507).

Almost surely, 2^100112013013 is an apocalyptic number.

It is an amenable number.

100112013013 is a deficient number, since it is larger than the sum of its proper divisors (1).

100112013013 is an equidigital number, since it uses as much as digits as its factorization.

100112013013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 100112013013 its reverse (310310211001), we get a palindrome (410422224014).

The spelling of 100112013013 in words is "one hundred billion, one hundred twelve million, thirteen thousand, thirteen".