Base | Representation |
---|---|
bin | 10110110000110100100101… |
… | …011001101111110100111001 |
3 | 111010110121121211002202100121 |
4 | 112300310211121233310321 |
5 | 101110213404133141303 |
6 | 552530454400333241 |
7 | 30041566121203564 |
oct | 2660644531576471 |
9 | 433417554082317 |
10 | 100112020208953 |
11 | 299982a6547165 |
12 | b28a469014221 |
13 | 43b26a504475c |
14 | 1aa163a4314db |
15 | b89223e1c9bd |
hex | 5b0d2566fd39 |
100112020208953 has 2 divisors, whose sum is σ = 100112020208954. Its totient is φ = 100112020208952.
The previous prime is 100112020208923. The next prime is 100112020209001. The reversal of 100112020208953 is 359802020211001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 92461551870249 + 7650468338704 = 9615693^2 + 2765948^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100112020208953 is a prime.
It is not a weakly prime, because it can be changed into another prime (100112020208903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056010104476 + 50056010104477.
It is an arithmetic number, because the mean of its divisors is an integer number (50056010104477).
Almost surely, 2100112020208953 is an apocalyptic number.
It is an amenable number.
100112020208953 is a deficient number, since it is larger than the sum of its proper divisors (1).
100112020208953 is an equidigital number, since it uses as much as digits as its factorization.
100112020208953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 34.
Adding to 100112020208953 its reverse (359802020211001), we get a palindrome (459914040419954).
The spelling of 100112020208953 in words is "one hundred trillion, one hundred twelve billion, twenty million, two hundred eight thousand, nine hundred fifty-three".
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