Base | Representation |
---|---|
bin | 10110110000110101100101… |
… | …111001101101100010011101 |
3 | 111010110201102020022012101101 |
4 | 112300311211321231202131 |
5 | 101110223113144030023 |
6 | 552531154014113101 |
7 | 30041635001113513 |
oct | 2660654571554235 |
9 | 433421366265341 |
10 | 100113102330013 |
11 | 2999880135a793 |
12 | b28a70b4ab791 |
13 | 43b28182a5586 |
14 | 1aa17000384b3 |
15 | b89288e211ad |
hex | 5b0d65e6d89d |
100113102330013 has 2 divisors, whose sum is σ = 100113102330014. Its totient is φ = 100113102330012.
The previous prime is 100113102329927. The next prime is 100113102330029. The reversal of 100113102330013 is 310033201311001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 94837642125444 + 5275460204569 = 9738462^2 + 2296837^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100113102330013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100113102730013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056551165006 + 50056551165007.
It is an arithmetic number, because the mean of its divisors is an integer number (50056551165007).
Almost surely, 2100113102330013 is an apocalyptic number.
It is an amenable number.
100113102330013 is a deficient number, since it is larger than the sum of its proper divisors (1).
100113102330013 is an equidigital number, since it uses as much as digits as its factorization.
100113102330013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 100113102330013 its reverse (310033201311001), we get a palindrome (410146303641014).
The spelling of 100113102330013 in words is "one hundred trillion, one hundred thirteen billion, one hundred two million, three hundred thirty thousand, thirteen".
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