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100113130133 is a prime number
BaseRepresentation
bin101110100111100110…
…1010010001010010101
3100120102001111221121122
41131033031102022111
53120012430131013
6113554043453325
710142616364652
oct1351715221225
9316361457548
10100113130133
1139504285485
121749b827245
13959609c753
144bba0acc29
15290e134a08
hex174f352295

100113130133 has 2 divisors, whose sum is σ = 100113130134. Its totient is φ = 100113130132.

The previous prime is 100113130127. The next prime is 100113130157. The reversal of 100113130133 is 331031311001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99945764164 + 167365969 = 316142^2 + 12937^2 .

It is a cyclic number.

It is not a de Polignac number, because 100113130133 - 220 = 100112081557 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100113130333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056565066 + 50056565067.

It is an arithmetic number, because the mean of its divisors is an integer number (50056565067).

Almost surely, 2100113130133 is an apocalyptic number.

It is an amenable number.

100113130133 is a deficient number, since it is larger than the sum of its proper divisors (1).

100113130133 is an equidigital number, since it uses as much as digits as its factorization.

100113130133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 100113130133 its reverse (331031311001), we get a palindrome (431144441134).

The spelling of 100113130133 in words is "one hundred billion, one hundred thirteen million, one hundred thirty thousand, one hundred thirty-three".