1001133001213 has 2 divisors, whose sum is σ = 1001133001214. Its totient is φ = 1001133001212.

The previous prime is 1001133001199. The next prime is 1001133001277. The reversal of 1001133001213 is 3121003311001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 887885944729 + 113247056484 = 942277^2 + 336522^2 .

It is a cyclic number.

It is not a de Polignac number, because 1001133001213 - 2⁵ = 1001133001181 is a prime.

It is a super-2 number, since 2×1001133001213² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001133001613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500566500606 + 500566500607.

It is an arithmetic number, because the mean of its divisors is an integer number (500566500607).

Almost surely, 2^{1001133001213} is an apocalyptic number.

It is an amenable number.

1001133001213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001133001213 is an equidigital number, since it uses as much as digits as its factorization.

1001133001213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1001133001213 its reverse (3121003311001), we get a palindrome (4122136312214).

The spelling of 1001133001213 in words is "one trillion, one billion, one hundred thirty-three million, one thousand, two hundred thirteen".