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100113302013013 is a prime number
BaseRepresentation
bin10110110000110101110001…
…110011011100010001010101
3111010110201221011001010222001
4112300311301303130101111
5101110224020303404023
6552531225510035301
730041642644310632
oct2660656163342125
9433421834033861
10100113302013013
11299988a4046563
12b28a766348b31
1343b284a77b4b3
141aa171c777189
15b8929b7166ad
hex5b0d71cdc455

100113302013013 has 2 divisors, whose sum is σ = 100113302013014. Its totient is φ = 100113302013012.

The previous prime is 100113302012987. The next prime is 100113302013031. The reversal of 100113302013013 is 310310203311001.

Together with next prime (100113302013031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89500549383729 + 10612752629284 = 9460473^2 + 3257722^2 .

It is a cyclic number.

It is not a de Polignac number, because 100113302013013 - 245 = 64928929924181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100113302013083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056651006506 + 50056651006507.

It is an arithmetic number, because the mean of its divisors is an integer number (50056651006507).

Almost surely, 2100113302013013 is an apocalyptic number.

It is an amenable number.

100113302013013 is a deficient number, since it is larger than the sum of its proper divisors (1).

100113302013013 is an equidigital number, since it uses as much as digits as its factorization.

100113302013013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 100113302013013 its reverse (310310203311001), we get a palindrome (410423505324014).

The spelling of 100113302013013 in words is "one hundred trillion, one hundred thirteen billion, three hundred two million, thirteen thousand, thirteen".