Base | Representation |
---|---|
bin | 11101001000110000011… |
… | …11001000110010100101 |
3 | 10112201002202020122211211 |
4 | 32210120033020302211 |
5 | 112400310301020232 |
6 | 2043525320031421 |
7 | 132221014414222 |
oct | 16443017106245 |
9 | 3481082218754 |
10 | 1001134001317 |
11 | 35664005396a |
12 | 142039902571 |
13 | 735391c2838 |
14 | 36652cb6949 |
15 | 1b0960b6a47 |
hex | e9183c8ca5 |
1001134001317 has 2 divisors, whose sum is σ = 1001134001318. Its totient is φ = 1001134001316.
The previous prime is 1001134001303. The next prime is 1001134001333. The reversal of 1001134001317 is 7131004311001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 789137295556 + 211996705761 = 888334^2 + 460431^2 .
It is a cyclic number.
It is not a de Polignac number, because 1001134001317 - 223 = 1001125612709 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1001134001017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500567000658 + 500567000659.
It is an arithmetic number, because the mean of its divisors is an integer number (500567000659).
Almost surely, 21001134001317 is an apocalyptic number.
It is an amenable number.
1001134001317 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001134001317 is an equidigital number, since it uses as much as digits as its factorization.
1001134001317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 1001134001317 its reverse (7131004311001), we get a palindrome (8132138312318).
The spelling of 1001134001317 in words is "one trillion, one billion, one hundred thirty-four million, one thousand, three hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •