10011341213 has 2 divisors, whose sum is σ = 10011341214. Its totient is φ = 10011341212.

The previous prime is 10011341183. The next prime is 10011341231. The reversal of 10011341213 is 31214311001.

Together with next prime (10011341231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9324219844 + 687121369 = 96562^2 + 26213^2 .

It is a cyclic number.

It is not a de Polignac number, because 10011341213 - 2⁶ = 10011341149 is a prime.

It is a super-2 number, since 2×10011341213² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10011341191 and 10011341200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10011341273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005670606 + 5005670607.

It is an arithmetic number, because the mean of its divisors is an integer number (5005670607).

Almost surely, 2^10011341213 is an apocalyptic number.

It is an amenable number.

10011341213 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011341213 is an equidigital number, since it uses as much as digits as its factorization.

10011341213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10011341213 its reverse (31214311001), we get a palindrome (41225652214).

The spelling of 10011341213 in words is "ten billion, eleven million, three hundred forty-one thousand, two hundred thirteen".