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100120012211099 is a prime number
BaseRepresentation
bin10110110000111100000001…
…110000110100001110011011
3111010111101020210110112021002
4112300330001300310032123
5101110331241111223344
6552534255412535215
730042301144123436
oct2660740160641633
9433441223415232
10100120012211099
11299a0727851711
12b28bb1962150b
1343b3379a173ca
141aa1b97a1681d
15b8954088844e
hex5b0f01c3439b

100120012211099 has 2 divisors, whose sum is σ = 100120012211100. Its totient is φ = 100120012211098.

The previous prime is 100120012211053. The next prime is 100120012211101. The reversal of 100120012211099 is 990112210021001.

It is a strong prime.

It is an emirp because it is prime and its reverse (990112210021001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100120012211099 - 232 = 100115717243803 is a prime.

It is a super-2 number, since 2×1001200122110992 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 100120012211101, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (100120012211299) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060006105549 + 50060006105550.

It is an arithmetic number, because the mean of its divisors is an integer number (50060006105550).

Almost surely, 2100120012211099 is an apocalyptic number.

100120012211099 is a deficient number, since it is larger than the sum of its proper divisors (1).

100120012211099 is an equidigital number, since it uses as much as digits as its factorization.

100120012211099 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 29.

The spelling of 100120012211099 in words is "one hundred trillion, one hundred twenty billion, twelve million, two hundred eleven thousand, ninety-nine".