1001200253519 has 2 divisors, whose sum is σ = 1001200253520. Its totient is φ = 1001200253518.

The previous prime is 1001200253509. The next prime is 1001200253527. The reversal of 1001200253519 is 9153520021001.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1001200253519 is a prime.

It is a super-2 number, since 2×1001200253519² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1001200253491 and 1001200253500.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001200253509) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500600126759 + 500600126760.

It is an arithmetic number, because the mean of its divisors is an integer number (500600126760).

Almost surely, 2^{1001200253519} is an apocalyptic number.

1001200253519 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001200253519 is an equidigital number, since it uses as much as digits as its factorization.

1001200253519 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2700, while the sum is 29.

The spelling of 1001200253519 in words is "one trillion, one billion, two hundred million, two hundred fifty-three thousand, five hundred nineteen".