Base | Representation |
---|---|
bin | 11101001000111000010… |
… | …11110111110000111011 |
3 | 10112201021100220122110022 |
4 | 32210130023313300323 |
5 | 112400424231112021 |
6 | 2043540044041055 |
7 | 132222450512606 |
oct | 16443413676073 |
9 | 3481240818408 |
10 | 1001200254011 |
11 | 356674495561 |
12 | 142057b3318b |
13 | 73549b4b809 |
14 | 3665ba0133d |
15 | 1b09bd021ab |
hex | e91c2f7c3b |
1001200254011 has 2 divisors, whose sum is σ = 1001200254012. Its totient is φ = 1001200254010.
The previous prime is 1001200254001. The next prime is 1001200254053. The reversal of 1001200254011 is 1104520021001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1001200254011 - 26 = 1001200253947 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1001200254001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500600127005 + 500600127006.
It is an arithmetic number, because the mean of its divisors is an integer number (500600127006).
Almost surely, 21001200254011 is an apocalyptic number.
1001200254011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001200254011 is an equidigital number, since it uses as much as digits as its factorization.
1001200254011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 1001200254011 its reverse (1104520021001), we get a palindrome (2105720275012).
The spelling of 1001200254011 in words is "one trillion, one billion, two hundred million, two hundred fifty-four thousand, eleven".
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