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1001200254053 is a prime number
BaseRepresentation
bin11101001000111000010…
…11110111110001100101
310112201021100220122111212
432210130023313301211
5112400424231112203
62043540044041205
7132222450512666
oct16443413676145
93481240818455
101001200254053
1135667449559a
12142057b33205
1373549b4b83c
143665ba0136d
151b09bd021d8
hexe91c2f7c65

1001200254053 has 2 divisors, whose sum is σ = 1001200254054. Its totient is φ = 1001200254052.

The previous prime is 1001200254011. The next prime is 1001200254083. The reversal of 1001200254053 is 3504520021001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 759968984644 + 241231269409 = 871762^2 + 491153^2 .

It is an emirp because it is prime and its reverse (3504520021001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1001200254053 - 210 = 1001200253029 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001200254083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500600127026 + 500600127027.

It is an arithmetic number, because the mean of its divisors is an integer number (500600127027).

Almost surely, 21001200254053 is an apocalyptic number.

It is an amenable number.

1001200254053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001200254053 is an equidigital number, since it uses as much as digits as its factorization.

1001200254053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 1001200254053 its reverse (3504520021001), we get a palindrome (4505720275054).

The spelling of 1001200254053 in words is "one trillion, one billion, two hundred million, two hundred fifty-four thousand, fifty-three".