Base | Representation |
---|---|
bin | 1001000110110001100111… |
… | …1110111111110100100001 |
3 | 1022110010201211012210102201 |
4 | 2101230121332333310201 |
5 | 2303014041201233323 |
6 | 33143241303413201 |
7 | 2052225544613644 |
oct | 221543176776441 |
9 | 38403654183381 |
10 | 10012004711713 |
11 | 3210081713674 |
12 | 1158488154201 |
13 | 57818827c834 |
14 | 268825615a5b |
15 | 12567dce48ad |
hex | 91b19fbfd21 |
10012004711713 has 2 divisors, whose sum is σ = 10012004711714. Its totient is φ = 10012004711712.
The previous prime is 10012004711701. The next prime is 10012004711741. The reversal of 10012004711713 is 31711740021001.
It is an a-pointer prime, because the next prime (10012004711741) can be obtained adding 10012004711713 to its sum of digits (28).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7034074665489 + 2977930046224 = 2652183^2 + 1725668^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10012004711713 is a prime.
It is not a weakly prime, because it can be changed into another prime (10012004711213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006002355856 + 5006002355857.
It is an arithmetic number, because the mean of its divisors is an integer number (5006002355857).
Almost surely, 210012004711713 is an apocalyptic number.
It is an amenable number.
10012004711713 is a deficient number, since it is larger than the sum of its proper divisors (1).
10012004711713 is an equidigital number, since it uses as much as digits as its factorization.
10012004711713 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1176, while the sum is 28.
Adding to 10012004711713 its reverse (31711740021001), we get a palindrome (41723744732714).
The spelling of 10012004711713 in words is "ten trillion, twelve billion, four million, seven hundred eleven thousand, seven hundred thirteen".
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