Base | Representation |
---|---|
bin | 10110110000111100000111… |
… | …101101111010000101101111 |
3 | 111010111101111202110000111211 |
4 | 112300330013231322011233 |
5 | 101110331442200040413 |
6 | 552534313342055251 |
7 | 30042303466223605 |
oct | 2660740755720557 |
9 | 433441452400454 |
10 | 100120112111983 |
11 | 299a0779185727 |
12 | b28bb46b7a527 |
13 | 43b3394624a62 |
14 | 1aa1ba6dbd875 |
15 | b8954951d83d |
hex | 5b0f07b7a16f |
100120112111983 has 2 divisors, whose sum is σ = 100120112111984. Its totient is φ = 100120112111982.
The previous prime is 100120112111977. The next prime is 100120112112043. The reversal of 100120112111983 is 389111211021001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100120112111983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100120112111923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060056055991 + 50060056055992.
It is an arithmetic number, because the mean of its divisors is an integer number (50060056055992).
Almost surely, 2100120112111983 is an apocalyptic number.
100120112111983 is a deficient number, since it is larger than the sum of its proper divisors (1).
100120112111983 is an equidigital number, since it uses as much as digits as its factorization.
100120112111983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 31.
Adding to 100120112111983 its reverse (389111211021001), we get a palindrome (489231323132984).
The spelling of 100120112111983 in words is "one hundred trillion, one hundred twenty billion, one hundred twelve million, one hundred eleven thousand, nine hundred eighty-three".
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