Base | Representation |
---|---|
bin | 10110110000111100001101… |
… | …000010001000110000011111 |
3 | 111010111101201222021021212121 |
4 | 112300330031002020300133 |
5 | 101110332133013113043 |
6 | 552534330245443411 |
7 | 30042305631301141 |
oct | 2660741502106037 |
9 | 433441658237777 |
10 | 100120201301023 |
11 | 299a0814562782 |
12 | b28bb70a10567 |
13 | 43b33a9c51837 |
14 | 1aa1bb4b98c91 |
15 | b89552289ded |
hex | 5b0f0d088c1f |
100120201301023 has 2 divisors, whose sum is σ = 100120201301024. Its totient is φ = 100120201301022.
The previous prime is 100120201301009. The next prime is 100120201301077. The reversal of 100120201301023 is 320103102021001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100120201301023 - 217 = 100120201169951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100120201300988 and 100120201301006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100120201301123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060100650511 + 50060100650512.
It is an arithmetic number, because the mean of its divisors is an integer number (50060100650512).
Almost surely, 2100120201301023 is an apocalyptic number.
100120201301023 is a deficient number, since it is larger than the sum of its proper divisors (1).
100120201301023 is an equidigital number, since it uses as much as digits as its factorization.
100120201301023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 100120201301023 its reverse (320103102021001), we get a palindrome (420223303322024).
The spelling of 100120201301023 in words is "one hundred trillion, one hundred twenty billion, two hundred one million, three hundred one thousand, twenty-three".
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