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10012088655589 is a prime number
BaseRepresentation
bin1001000110110001111011…
…1111001101111011100101
31022110010221200011120210011
42101230132333031323211
52303014224143434324
633143253502530221
72052230614254166
oct221543677157345
938403850146704
1010012088655589
113210115038979
1211584b0296971
1357819c791077
1426883282776d
15125686376c94
hex91b1efcdee5

10012088655589 has 2 divisors, whose sum is σ = 10012088655590. Its totient is φ = 10012088655588.

The previous prime is 10012088655539. The next prime is 10012088655649. The reversal of 10012088655589 is 98555688021001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7903688822500 + 2108399833089 = 2811350^2 + 1452033^2 .

It is a cyclic number.

It is not a de Polignac number, because 10012088655589 - 225 = 10012055101157 is a prime.

It is a super-3 number, since 3×100120886555893 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10012088655539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006044327794 + 5006044327795.

It is an arithmetic number, because the mean of its divisors is an integer number (5006044327795).

Almost surely, 210012088655589 is an apocalyptic number.

It is an amenable number.

10012088655589 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012088655589 is an equidigital number, since it uses as much as digits as its factorization.

10012088655589 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912000, while the sum is 58.

The spelling of 10012088655589 in words is "ten trillion, twelve billion, eighty-eight million, six hundred fifty-five thousand, five hundred eighty-nine".