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100121011211141 is a prime number
BaseRepresentation
bin10110110000111100111101…
…010011101100101110000101
3111010111110211102020222200122
4112300330331103230232011
5101110340312332224031
6552534542500551325
730042334664361134
oct2660747523545605
9433443742228618
10100121011211141
11299a109a752188
12b2901580b2545
1343b34a89943ab
141aa1c5058391b
15b8959d41d47b
hex5b0f3d4ecb85

100121011211141 has 2 divisors, whose sum is σ = 100121011211142. Its totient is φ = 100121011211140.

The previous prime is 100121011211069. The next prime is 100121011211153. The reversal of 100121011211141 is 141112110121001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78675498546241 + 21445512664900 = 8869921^2 + 4630930^2 .

It is a cyclic number.

It is not a de Polignac number, because 100121011211141 - 210 = 100121011210117 is a prime.

It is a super-3 number, since 3×1001210112111413 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100121811211141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060505605570 + 50060505605571.

It is an arithmetic number, because the mean of its divisors is an integer number (50060505605571).

Almost surely, 2100121011211141 is an apocalyptic number.

It is an amenable number.

100121011211141 is a deficient number, since it is larger than the sum of its proper divisors (1).

100121011211141 is an equidigital number, since it uses as much as digits as its factorization.

100121011211141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 17.

Adding to 100121011211141 its reverse (141112110121001), we get a palindrome (241233121332142).

The spelling of 100121011211141 in words is "one hundred trillion, one hundred twenty-one billion, eleven million, two hundred eleven thousand, one hundred forty-one".